6(2x^2)=36

Solution for 6(2x^2)=36 equation:

6(2x^2)=36

We move all terms to the left:

6(2x^2)-(36)=0

a = 62; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·62·(-36)
Δ = 8928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8928}=\sqrt{144*62}=\sqrt{144}*\sqrt{62}=12\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{62}}{2*62}=\frac{0-12\sqrt{62}}{124}
=-\frac{12\sqrt{62}}{124}
=-\frac{3\sqrt{62}}{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{62}}{2*62}=\frac{0+12\sqrt{62}}{124}
=\frac{12\sqrt{62}}{124}
=\frac{3\sqrt{62}}{31}
$